SSC CGL Maths Special Quiz: 28.05.2021
Question 1
समाधान :
…(i)
…(ii)
Squaring both the equations and adding.
Question 2
समाधान :
Expression,
= 2 3√3×3×3×5 - 3√2×2×2×3×3×3×5 + 3√2×2×2×2×2×2×5 – 2 3√2×2×2×5
= 6 3√5 – 6 3√5 + 4 3√5 – 4 3√5
= 0
Question 3
समाधान :
दशमलव स्थानों पर समान संख्या बनाना, दी गई संख्याएं 1.5, 3.0 एवं 0.6 हो जाती हैं|
प्रत्येक में दशमलव स्थानों की संख्या = 1
प्रत्येक में दशमलव के बिना स्थान = 1
दशमलव के बिना, ये संख्याएं 15, 30, 6 हैं
15, 30, 6 का म.स.प. = 3
∴दी गई संख्याओं का म.स.प. = 0.3,
15, 30, 6 का ल.स.प. = (3 ×2 × 5) = 30,
∴दी गई संख्याओं का ल.स.प. = 3.0,
Question 4
समाधान :
Let the coordinates of point B be (x’’, y’’), then
Mid-point (a, b) =
So, x’’ = 2a – x’ and y’’ = 2b – y’
⇒ Coordinates of B = (4 – 11, 2 – 5)
= (-7 , -3)
Question 5
समाधान :
sum doubles itself in 6 yr at compound interest.
it will double itself again in another 6 years and so on..
We know that
23 = 8
∴Required time = 6 × 3 = 18 yr
Alternate Method:
Let assume that, initial amount = Rs. P
after 6 years the amount will be 2P.
Since amount is doubling in every 6 years then
After 12 years the amount will be 2x (2P) = 4P.
After another 6 years i.e. 18 years later the amount will again doubled.
So, in 18 years the amount will be 2 x (4P) = 8P means 8 times the initial amount.
Question 6
समाधान :
If A completes the work in x days, B will take 2x days
+
⇒ 2x = 42
x = 21
Hence Option B is correct
Question 7
समाधान :
Area of a trapezium = 1/2 (sum of parallel sides) x (perpendicular distance between them) = 1/2 (24 + 16) x (15) = 300 cm2
Question 8
समाधान :
Triangle ABC is a right angle
∠B = 90°
∠A = 60°
∠C = 180 - 90 - 60 = 30°
Question 9
समाधान :
Question 10
समाधान :
Since, 1 Rs : 50 paisa : 10 paisa = 100 : 50 : 10
= 10 : 5 : 1
Let there are 6x, 3x and 2x no. of rupee, Rs1, 50paisa and 10 paisa
According to the question, total money in the bag:
6x × 10 + 3x × 5 + 2x × 1 = 30.8 × 100
⇒ 77x = 3080
⇒ x = 40
∴ Number of 50 paise coin = 40 × 3 = 120
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